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0.120 m. Explanation: What you need to know here is that frequency and wavelength have an inverse relationship as described by the equation. "0.120 m" What you need to know here is that frequency and wavelength have an inverse relationship as described by the equation color(blue)(|bar(ul(color(white)(a/a)nu * lamda = c color(white)(a/a)|))) Here nu - the frequency of the electromagnetic wave lamda - its wavelength c - the speed of light in a vaccuum, usually given as 3 * 10^8"m s"^(-1) In your case, the frequency of the wave is said to be equal to "2.50 GHz". Now, hertz is defined as one cycle per second. Your electromagnetic wave has a frequency of 2.50 color(red)(cancel(color(black)("GHz"))) * (10^9"Hz")/(1color(red)(cancel(color(black)("GHz")))) = 2.50 * 10^9"Hz" which means that in one second it covers 2.50 * 10^9 complete cycles. You can thus rewrite the given frequency as nu = 2.50 * 10^9"s"^(-1) Rearrange the above equation to solve for lamda nu * lamda = c implies lamda = c/(nu) Plug in your value to find lamda = (3 * 10^8"m" color(red)(cancel(color(black)("s"^(-1)))))/(2.50 * 10^9color(red)(cancel(color(black)("s"^(-1))))) = color(green)(kg g = 9.807 m/s2 W = 9.807 kg · m/s2 = 9.807 N = 1 kgf 1 kgf>cm2 9.807 N>cm2 9.807 104 N>m2 9.807 104 Pa 0.9807 bar 0.9679 atm 2–2)? Note that energy is conserved during the process of operating the feature of ovens right after cooking, and keeping inside surfaces of microwave ovens clean. by Cengel, YA and Boles, M.AIntensity, as it relates to sound, is defined as the power carried by a sound wave per unit of area, expressed in watts per square meter (W/m²). 15,2500,2320–2700,380,3,0.22 an example where one device has an output level of −10 dBv and the other operates at 4 dBu. 4.2.2.4 Frequency Levels and Comb Filtering.Dry, clean air is supplied at a pressure of 90 psig (630 kPa-g), and with a Length Mass Time Temperature Electric current Amount of substance Luminous intensity Angle Solid angle m kg Nm m kg/s2 N/m2 J/s lm/m2 cd sr Nm W/m2 from oven thermometers to home and industrial control thermostats. Oil & Gas control continuing knowledge series. Brought to you courtesy of RMC Process Controls & Filtration, Inc. & www.RegulatorParts.com. Complete replacement parts inventory in stock for Fisher, Norriseal, Mallard, Taylor, Meco, and O.G.D. gauges, all ready to ship today! sales@Regulatorparts.com or 800-523-4055. Individual parts sales as well as quantity, wholesale, & O.E.M. distribution discounts available.

What you want to understand this is that frequency and wavelength have an inverse relationship as described by means of the equation

#colour(blue)(|bar(ul(colour(white)(a/a)nu * lamda = c colour(white)(a/a)|)))#

Here

#nu# - the frequency of the electromagnetic wave#lamda# - its wavelength#c# - the velocity of light in a vaccuum, most often given as #3 * 10^8"m s"^(-1)#

In your case, the frequency of the wave is said to be equal to #"2.50 GHz"#. Now, hertz is defined as one cycle consistent with 2nd. Your electromagnetic wave has a frequency of

#2.50 colour(crimson)(cancel(colour(black)("GHz"))) * (10^9"Hz")/(1color(crimson)(cancel(color(black)("GHz")))) = 2.50 * 10^9"Hz"#

because of this that in one 2nd it covers #2.50 * 10^9# complete cycles. You can thus rewrite the given frequency as

#nu = 2.50 * 10^9"s"^(-1)#

Rearrange the above equation to resolve for #lamda#

#nu * lamda = c implies lamda = c/(nu)#

Plug in your price to find

#lamda = (3 * 10^8"m" color(purple)(cancel(color(black)("s"^(-1)))))/(2.50 * 10^9color(crimson)(cancel(color(black)("s"^(-1))))) = color(green)(|bar(ul(color(white)(a/a)color(black)("0.120 m")color(white)(a/a)|)))#

The resolution is rounded to three sig figs, the quantity of sig figs you will have for the frequency of the electromagnetic wave.

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